Let’s analyze the given reactions and clues for each compound.
Step 1: Analyzing A:
- A shows positive Lassaigne’s test for nitrogen (N), which means A contains nitrogen.
- The molar mass of A is 121 g/mol.
- Based on the structure options, the compound with a molecular formula that fits these criteria is \(\text{CONH}_2\) (amide group).
This is the structure of \(\text{benzamide}\), which fits the molar mass and the positive Lassaigne’s test for nitrogen.
Step 2: Analyzing B:
- B gives effervescence with aqueous NaHCO3.
This suggests B contains a carboxyl group (-COOH), as carboxylic acids react with NaHCO3 to release carbon dioxide (CO2).
- Therefore, B corresponds to a carboxylic acid group, specifically \(\text{CO}_2\text{H}\), which matches the second compound in the options.
Step 3: Analyzing C:
- C gives a fruity smell, which is characteristic of an ester group.
- The ester functional group in the options is \(\text{CO}_2\text{Et}\) (ethyl ester), which corresponds to the third structure in the options.
Step 4: Final Identification:
- A is \(\text{CONH}_2\) (benzamide),
- B is \(\text{CO}_2\text{H}\) (carboxylic acid),
- C is \(\text{CO}_2\text{Et}\) (ethyl ester).
Thus, the correct answer is Option (1):
A = CONH2, B = CO2H, C = CO2Et