Question:

A set S contains 7 elements. A non-empty subset A of S and an element x of S are chosen at random. Then the probability that \(x \in A\) is:

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For a fixed x, count the non-empty subsets containing x (64) out of all non-empty subsets (127).
Updated On: Nov 11, 2026
  • \(\frac{1}{2}\)
  • \(\frac{64}{127}\)
  • \(\frac{63}{128}\)
  • \(\frac{31}{128}\)
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The Correct Option is B

Solution and Explanation

The number of non-empty subsets of S is \(2^7 - 1 = 127\).
Fix an element x. The subsets containing x are formed by choosing any subset of the other 6 elements: \(2^6 = 64\), all non-empty.
By symmetry the probability is the same for every x, so \(P(x\in A) = \frac{64}{127}\).
Answer: (2) \(\frac{64}{127}\)
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