In DNA, the nitrogenous bases follow a specific base-pairing rule: Adenine (A) pairs with Thymine (T), and Guanine (G) pairs with Cytosine (C). This means the amount of Adenine is equal to the amount of Thymine, and the amount of Guanine is equal to the amount of Cytosine.
We are given that the DNA sequence has 300 nitrogenous base pairs, and 75 of them are Guanine. Since Guanine pairs with Cytosine, the number of Cytosine will also be
75. Therefore, the total number of Guanine and Cytosine combined is:
75 + 75 = 150 base pairs.
The total number of base pairs is
300. After accounting for the 150 base pairs of Guanine and Cytosine, the remaining base pairs are:
300 - 150 = 150 base pairs.
Since Adenine pairs with Thymine in a 1:1 ratio, the number of Thymine will be half of the remaining base pairs:
(150)/(2) = 75 Thymine base pairs.
The number of Thymine in this DNA sequence is 100, so the correct answer is (B).
Final Answer: 100.