A sandstone sample with 100 % quartz has a porosity of 30 %. The sample is dry and the density of quartz is 2.65 g/cc. The bulk density of the sandstone sample is ............ g/cc. (Round off to one decimal place)
Given:
- Porosity (\(\phi\)) = 30% = 0.30
- Density of quartz (\(\rho_q\)) = 2.65 g/cc
- The sample is 100% quartz, so the non-porous fraction is 70% (since 30% is porosity).
Step 1: The bulk density \(\rho_b\) can be calculated using the formula:
\[ \rho_b = (1 - \phi) \times \rho_q \]
Step 2: Substitute the known values into the formula:
\[ \rho_b = (1 - 0.30) \times 2.65 \]
Step 3: Simplify the calculation:
\[ \rho_b = 0.70 \times 2.65 = 1.855 \, \text{g/cc} \]
Step 4: Round to one decimal place:
\[ \rho_b = 1.9 \, \text{g/cc} \]
Thus, the bulk density of the sandstone sample is **1.9 g/cc**.
\[ \boxed{1.9 \, \text{g/cc}} \]
