Question:

A s-block element (M) reacts with oxygen to form an oxide of the formula \(\mathrm{MO_2}\). The oxide is pale yellow in colour and paramagnetic. The element (M) is :

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A paramagnetic MO2 contains the superoxide ion O2- (one unpaired electron). Among the options, K forms a stable superoxide, KO2.
Updated On: Nov 4, 2026
  • Mg
  • Na
  • Ca
  • K
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The Correct Option is D

Solution and Explanation

For an oxide of formula \(\mathrm{MO_2}\) with a group 1 metal, the anion is the superoxide \(\mathrm{O_2^-}\), which has one unpaired electron and so is paramagnetic and coloured.
The larger alkali metals (K, Rb, Cs) form stable superoxides on burning in excess oxygen: \(\mathrm{K + O_2 \rightarrow KO_2}\), a yellow paramagnetic solid.
Na gives mainly \(\mathrm{Na_2O_2}\) (diamagnetic peroxide); Mg and Ca give normal oxides MgO and CaO.
Answer: (4) K
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