Question:

A rod has volume \(V\) and Young's modulus \(Y\) and is subjected to stress \(\tau\). Find elastic energy stored in the rod.

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Elastic energy density in a stretched body: \[ u = \frac{1}{2}\times \text{stress} \times \text{strain} \] Total energy = energy density \(\times\) volume.
Updated On: Apr 6, 2026
  • \( \dfrac{1}{2}\dfrac{\tau^2 V}{Y} \)
  • \( \dfrac{1}{2}\dfrac{\tau V}{Y} \)
  • \( \dfrac{1}{2}\dfrac{\tau V}{Y^2} \)
  • \( \dfrac{1}{2}\dfrac{\tau V^2}{Y} \)
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The Correct Option is A

Solution and Explanation

Concept: Elastic potential energy stored in a stretched material is \[ U = \frac{1}{2}\times \text{Stress} \times \text{Strain} \times \text{Volume} \] Also, \[ Y = \frac{\text{Stress}}{\text{Strain}} \]
Step 1:
Find strain. \[ \text{Strain} = \frac{\text{Stress}}{Y} \] \[ \text{Strain} = \frac{\tau}{Y} \]
Step 2:
Substitute in energy expression. \[ U = \frac{1}{2} \times \tau \times \frac{\tau}{Y} \times V \] \[ U = \frac{1}{2}\frac{\tau^2 V}{Y} \] \[ \boxed{U = \frac{1}{2}\frac{\tau^2 V}{Y}} \]
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