Question

A rock specimen was tested under compression. The lateral and longitudinal strains were found to be \(0.8\%\) and \(4\%\) respectively. The Poisson's ratio of the specimen is

• A. \(0.2\)
• B. \(0.6\)
• C. \(0.5\)
• D. \(0.13\)

Hint:

Poisson's ratio is \[ \boxed{ \mu = \frac{\text{Lateral strain}} {\text{Longitudinal strain}} } \] (using the magnitudes of the strains).

Answer 1

The Correct Option is A

Step 1: Recall the definition of Poisson's ratio. Poisson's ratio is \[ \mu = \frac{\text{Lateral strain}} {\text{Longitudinal strain}}. \]

Step 2: Substitute the given values. Given, \[ \text{Lateral strain}=0.8\%, \] and \[ \text{Longitudinal strain}=4\%. \] Therefore, \[ \mu = \frac{0.8}{4} = 0.2. \] Hence, \[ \boxed{0.2} \] is the correct answer. Therefore, \[ \boxed{(A)} \] is the correct answer.