For each activity, the expected time using PERT is
\[
t_e = \frac{a + 4m + b}{6}
\]
Compute for each activity:
A:
\[
t_e = \frac{4 + 4(5) + 6}{6} = \frac{30}{6} = 5
\]
B:
\[
t_e = \frac{1 + 4(3) + 5}{6} = \frac{18}{6} = 3
\]
C:
\[
t_e = \frac{1 + 4(2) + 3}{6} = \frac{12}{6} = 2
\]
D (depends on C):
\[
t_e = \frac{2 + 4(4) + 6}{6} = \frac{24}{6} = 4
\]
E (depends on B and D):
\[
t_e = \frac{3 + 4(4) + 5}{6} = \frac{24}{6} = 4
\]
Now determine the critical path:
Paths:
1. A → B → E:
\[
5 + 3 + 4 = 12
\]
2. A → C → D → E:
\[
5 + 2 + 4 + 4 = 15
\]
Critical path = A–C–D–E, duration = 15 weeks.
Thus,
\[
\boxed{15\ \text{weeks}}
\]