Question:

A process will be spontaneous at all temperatures if :

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Spontaneity needs \(\Delta G=\Delta H-T\Delta S \lt 0\); find the sign combination that makes this true for every T.
Updated On: Nov 5, 2026
  • \(\Delta H \lt 0\) and \(\Delta S \gt 0\)
  • \(\Delta H \lt 0\) and \(\Delta S \lt 0\)
  • \(\Delta H \gt 0\) and \(\Delta S \lt 0\)
  • \(\Delta H \gt 0\) and \(\Delta S \gt 0\)
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The Correct Option is A

Solution and Explanation

\(\Delta G = \Delta H - T\Delta S\). The process is spontaneous when \(\Delta G \lt 0\).
For \(\Delta H \lt 0\) and \(\Delta S \gt 0\): \(\Delta H\) is negative and \(-T\Delta S\) is negative, so \(\Delta G \lt 0\) at every temperature.
\(\Delta H \lt 0, \Delta S \lt 0\): spontaneous only at low T. \(\Delta H \gt 0, \Delta S \lt 0\): never spontaneous. \(\Delta H \gt 0, \Delta S \gt 0\): spontaneous only at high T.
Answer: (1) \(\Delta H \lt 0\) and \(\Delta S \gt 0\)
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