Question:

A process has \(\Delta\)H = 200 J mol\(^{-1}\) and \(\Delta\)S = 40 JK\(^{-1}\) mol\(^{-1}\). Out of the values given below, choose the minimum temperature above which the process will be spontaneous :

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Spontaneous when \(\Delta G = \Delta H - T\Delta S \lt 0\), i.e. when \(T \gt \Delta H/\Delta S\).
Updated On: Nov 5, 2026
  • 4 K
  • 20 K
  • 5 K
  • 12 K
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The Correct Option is C

Solution and Explanation

\(\Delta G = \Delta H - T\Delta S\). The process is spontaneous when \(\Delta G \lt 0\), i.e. \(T \gt \Delta H/\Delta S\).
\(T_{min} = \dfrac{200\ \mathrm{J\,mol^{-1}}}{40\ \mathrm{J\,K^{-1}\,mol^{-1}}} = 5\) K.
The process becomes spontaneous above 5 K, so among the given values the minimum (threshold) temperature is 5 K.
Answer: (3) 5 K
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