Question

A plot of \(\ln k\) versus \(1/T\) indicates

• A. Vant's-Hoff isotherm
• B. Cox chart
• C. Bode plot
• D. Arrhenius plot

Hint:

Arrhenius equation gives \(\ln k=\ln A-\frac{E_a}{RT}\), so \(\ln k\) versus \(1/T\) is an Arrhenius plot.

Answer 1

The Correct Option is D

The Arrhenius equation relates rate constant \(k\) with temperature \(T\). It is given by: \[ k=Ae^{-E_a/RT} \] Taking natural logarithm on both sides: \[ \ln k=\ln A-\frac{E_a}{RT} \] This equation is of the form: \[ y=c+mx \] where, \[ y=\ln k \] and \[ x=\frac{1}{T} \] So a plot of: \[ \ln k \] against: \[ \frac{1}{T} \] is a straight line. This plot is called Arrhenius plot. The slope is: \[ -\frac{E_a}{R} \] Therefore, a plot of \(\ln k\) versus \(1/T\) indicates: \[ \text{Arrhenius plot} \]