Question

A particle of mass \(m\) is executing oscillation about the origin on X-axis. Its potential energy is \(V(x) = K|x|^3\). Where \(K\) is a positive constant. If the amplitude of oscillation is \(a\), then its time period \(T\) is proportional to

• A. \(\frac {1}{\sqrt a}\)
• B. \(a\)
• C. \(\sqrt a\)
• D. \(a^{\frac 32}\)

Answer 1

The Correct Option is A

The correct option is (A): \(\frac {1}{\sqrt a}\).