Comprehension
A newsstand will display exactly one copy each of six different magazines— M, O, P, S, T, and V— in a single row on a rack. Each magazine will occupy exactly one of the six positions, numbered consecutively 1 through 6. The magazines must be displayed in accordance with the following rules:
Either P or else T occupies position 1.
Either S or else T occupies position 6.
M and O, not necessarily in that order, occupy consecutively numbered positions.
V and T, not necessarily in that order, occupy consecutively numbered positions.
Question: 1
Which of the following is an order in which the six magazines can be arranged, from position 1 through position 6?
Which of the following is an order in which the six magazines can be arranged, from position 1 through position 6?
Show Hint
For "which of the following could be true" questions, the most efficient method is to check the options against the rules. Start with the most restrictive or simplest rule (e.g., who can be first or last) to eliminate options quickly.
Updated On: Oct 1, 2025
- M, O, P, S, V, T
- P, O, S, M, V, T
- P, V, T, O, M, S
- P, V, T, S, O, M
- T, P, V, M, O, S
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
This question asks to identify a valid arrangement of the magazines that satisfies all the given rules. We can test each option against the rules one by one.
Step 2: Detailed Explanation:
Let's check each option:
(A) M, O, P, S, V, T \begin{itemize} \item Rule 1: Position 1 must be P or T. Here it is M. Fails. \end{itemize} (B) P, O, S, M, V, T \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: T is in position 6. (Ok) \item Rule 3: M and O must be consecutive. Here, O is in position 2 and M is in position 4. They are not consecutive. Fails. \end{itemize} (C) P, V, T, O, M, S \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: S is in position 6. (Ok) \item Rule 3: M and O are consecutive ([OM] block in positions 4 and 5). (Ok) \item Rule 4: V and T are consecutive ([VT] block in positions 2 and 3). (Ok) \item All rules are satisfied. This is a valid arrangement. \end{itemize} (D) P, V, T, S, O, M \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: M is in position 6. It must be S or T. Fails. \end{itemize} (E) T, P, V, M, O, S \begin{itemize} \item Rule 1: T is in position 1. (Ok) \item Rule 4: V and T must be consecutive. Here, T is in position 1 and V is in position 3. They are not consecutive. Fails. \end{itemize} Step 3: Final Answer:
Only option (C) satisfies all the rules of the setup. Therefore, it is a possible arrangement.
This question asks to identify a valid arrangement of the magazines that satisfies all the given rules. We can test each option against the rules one by one.
Step 2: Detailed Explanation:
Let's check each option:
(A) M, O, P, S, V, T \begin{itemize} \item Rule 1: Position 1 must be P or T. Here it is M. Fails. \end{itemize} (B) P, O, S, M, V, T \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: T is in position 6. (Ok) \item Rule 3: M and O must be consecutive. Here, O is in position 2 and M is in position 4. They are not consecutive. Fails. \end{itemize} (C) P, V, T, O, M, S \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: S is in position 6. (Ok) \item Rule 3: M and O are consecutive ([OM] block in positions 4 and 5). (Ok) \item Rule 4: V and T are consecutive ([VT] block in positions 2 and 3). (Ok) \item All rules are satisfied. This is a valid arrangement. \end{itemize} (D) P, V, T, S, O, M \begin{itemize} \item Rule 1: P is in position 1. (Ok) \item Rule 2: M is in position 6. It must be S or T. Fails. \end{itemize} (E) T, P, V, M, O, S \begin{itemize} \item Rule 1: T is in position 1. (Ok) \item Rule 4: V and T must be consecutive. Here, T is in position 1 and V is in position 3. They are not consecutive. Fails. \end{itemize} Step 3: Final Answer:
Only option (C) satisfies all the rules of the setup. Therefore, it is a possible arrangement.
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Question: 2
If P occupies position 3, which of the following must be true?
If P occupies position 3, which of the following must be true?
Show Hint
When given a new condition, start by applying the most powerful rules to it. Here, the position of P immediately determines the position of T (Rule 1), which in turn determines the positions of S (Rule 2) and V (Rule 4), quickly filling most of the board.
Updated On: Oct 1, 2025
- M occupies position 4.
- O occupies position 2.
- S occupies position 5.
- T occupies position 6.
- V occupies position 2.
Show Solution
Verified By Collegedunia
The Correct Option is
Solution and Explanation
Step 1: Understanding the Concept:
This question presents a new condition ("If P occupies position 3...") and asks for a conclusion that must logically follow. We need to use this new condition in conjunction with the original rules to determine the fixed position of other magazines.
Step 2: Detailed Explanation:
Let's build the arrangement based on the new condition.
\begin{enumerate} \item Condition: P is in position 3. (\_ \_ P \_ \_ \_) \item Apply Rule 1 (P/T in 1): Since P is not in position 1, T must be in position 1. (T \_ P \_ \_ \_) \item Apply Rule 2 (S/T in 6): Since T is in position 1, it cannot be in position 6. Therefore, S must be in position 6. (T \_ P \_ \_ S) \item Apply Rule 4 ([VT]/[TV] block): Since T is in position 1, V must be in position 2 to form the [TV] block. (T V P \_ \_ S) \item Apply Rule 3 ([MO]/[OM] block): The remaining magazines are M and O. The remaining positions are 4 and 5. Since M and O must be in consecutive positions, they must occupy positions 4 and 5. The order can be either M-O or O-M. \end{enumerate} The complete arrangement is: T(1), V(2), P(3), M/O(4), O/M(5), S(6).
Step 3: Evaluate the Options:
Now we check which of the given options \textit{must} be true based on this deduction.
(A) M occupies position 4. (This could be true, but O could also be in position 4). (B) O occupies position 2. (This is false; V must be in position 2). (C) S occupies position 5. (This is false; S must be in position 6). (D) T occupies position 6. (This is false; T must be in position 1). (E) V occupies position 2. (This is a certain deduction from our steps above. It must be true).
Step 4: Final Answer:
Given that P is in position 3, it is a logical necessity that V must be in position 2. Therefore, option (E) is the correct answer.
This question presents a new condition ("If P occupies position 3...") and asks for a conclusion that must logically follow. We need to use this new condition in conjunction with the original rules to determine the fixed position of other magazines.
Step 2: Detailed Explanation:
Let's build the arrangement based on the new condition.
\begin{enumerate} \item Condition: P is in position 3. (\_ \_ P \_ \_ \_) \item Apply Rule 1 (P/T in 1): Since P is not in position 1, T must be in position 1. (T \_ P \_ \_ \_) \item Apply Rule 2 (S/T in 6): Since T is in position 1, it cannot be in position 6. Therefore, S must be in position 6. (T \_ P \_ \_ S) \item Apply Rule 4 ([VT]/[TV] block): Since T is in position 1, V must be in position 2 to form the [TV] block. (T V P \_ \_ S) \item Apply Rule 3 ([MO]/[OM] block): The remaining magazines are M and O. The remaining positions are 4 and 5. Since M and O must be in consecutive positions, they must occupy positions 4 and 5. The order can be either M-O or O-M. \end{enumerate} The complete arrangement is: T(1), V(2), P(3), M/O(4), O/M(5), S(6).
Step 3: Evaluate the Options:
Now we check which of the given options \textit{must} be true based on this deduction.
(A) M occupies position 4. (This could be true, but O could also be in position 4). (B) O occupies position 2. (This is false; V must be in position 2). (C) S occupies position 5. (This is false; S must be in position 6). (D) T occupies position 6. (This is false; T must be in position 1). (E) V occupies position 2. (This is a certain deduction from our steps above. It must be true).
Step 4: Final Answer:
Given that P is in position 3, it is a logical necessity that V must be in position 2. Therefore, option (E) is the correct answer.
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Question: 3
If O and T, not necessarily in that order, occupy consecutively numbered positions, then T can be in position
If O and T, not necessarily in that order, occupy consecutively numbered positions, then T can be in position
Show Hint
In logic games, when a new rule connects existing blocks (like O and T here), look for the creation of a larger "super-block." This dramatically reduces the number of possible arrangements and often leads directly to the solution.
Updated On: Oct 1, 2025
- 1
- 2
- 4
- 5
- 6
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
This question introduces a new condition that combines with the original rules to limit the possibilities. We need to find the possible positions for T under this new constraint.
Step 2: Key Deductions from the New Condition:
\begin{enumerate} \item Original Rule 3: M and O are consecutive ([MO]/[OM]). \item Original Rule 4: V and T are consecutive ([VT]/[TV]). \item New Condition: O and T are consecutive ([OT]/[TO]). \end{enumerate} Combining these three block rules, we can deduce a larger structure. O must be next to M and T. T must be next to O and V. This forces a 4-magazine chain: M-O-T-V or its reverse V-T-O-M. In both cases, O and T are internal to the block.
Step 3: Placing the 4-Magazine Block:
This [MOTV/VTOM] block must be placed in the 6 available positions. The two remaining magazines are P and S. Let's test the possible placements of the 4-magazine block. \begin{itemize} \item Placement 1: Block in positions 1-4. The magazine in position 1 would be M or V. This violates Rule 1, which requires P or T in position 1. So this placement is not allowed. \item Placement 2: Block in positions 3-6. The magazine in position 6 would be V or M. This violates Rule 2, which requires S or T in position 6. So this placement is not allowed. \item Placement 3: Block in positions 2-5. This is the only remaining possibility. Positions 1 and 6 are left open for P and S. \end{itemize} Step 4: Determining the Final Arrangement and T's Position:
With the 4-magazine block in positions 2-5, we must satisfy Rules 1 and 2 for the remaining slots. \begin{itemize} \item For position 1, Rule 1 requires P or T. Since T is inside the block (in position 3 or 4), P must be in position 1. \item For position 6, Rule 2 requires S or T. Since T is inside the block, S must be in position 6. \end{itemize} The only valid arrangement structure is: P, [4-magazine block], S.
Now let's see where T can be: \begin{itemize} \item If the block is M-O-T-V in positions 2-5, then T is in position 4. (Arrangement: P, M, O, T, V, S) \item If the block is V-T-O-M in positions 2-5, then T is in position 3. (Arrangement: P, V, T, O, M, S) \end{itemize} So, under this condition, T can be in position 3 or position 4.
Step 5: Final Answer:
Looking at the options, only position 4 is listed. Since we have proven that T can be in position 4, this is the correct answer.
This question introduces a new condition that combines with the original rules to limit the possibilities. We need to find the possible positions for T under this new constraint.
Step 2: Key Deductions from the New Condition:
\begin{enumerate} \item Original Rule 3: M and O are consecutive ([MO]/[OM]). \item Original Rule 4: V and T are consecutive ([VT]/[TV]). \item New Condition: O and T are consecutive ([OT]/[TO]). \end{enumerate} Combining these three block rules, we can deduce a larger structure. O must be next to M and T. T must be next to O and V. This forces a 4-magazine chain: M-O-T-V or its reverse V-T-O-M. In both cases, O and T are internal to the block.
Step 3: Placing the 4-Magazine Block:
This [MOTV/VTOM] block must be placed in the 6 available positions. The two remaining magazines are P and S. Let's test the possible placements of the 4-magazine block. \begin{itemize} \item Placement 1: Block in positions 1-4. The magazine in position 1 would be M or V. This violates Rule 1, which requires P or T in position 1. So this placement is not allowed. \item Placement 2: Block in positions 3-6. The magazine in position 6 would be V or M. This violates Rule 2, which requires S or T in position 6. So this placement is not allowed. \item Placement 3: Block in positions 2-5. This is the only remaining possibility. Positions 1 and 6 are left open for P and S. \end{itemize} Step 4: Determining the Final Arrangement and T's Position:
With the 4-magazine block in positions 2-5, we must satisfy Rules 1 and 2 for the remaining slots. \begin{itemize} \item For position 1, Rule 1 requires P or T. Since T is inside the block (in position 3 or 4), P must be in position 1. \item For position 6, Rule 2 requires S or T. Since T is inside the block, S must be in position 6. \end{itemize} The only valid arrangement structure is: P, [4-magazine block], S.
Now let's see where T can be: \begin{itemize} \item If the block is M-O-T-V in positions 2-5, then T is in position 4. (Arrangement: P, M, O, T, V, S) \item If the block is V-T-O-M in positions 2-5, then T is in position 3. (Arrangement: P, V, T, O, M, S) \end{itemize} So, under this condition, T can be in position 3 or position 4.
Step 5: Final Answer:
Looking at the options, only position 4 is listed. Since we have proven that T can be in position 4, this is the correct answer.
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Question: 4
Which of the following can be true?
Which of the following can be true?
Show Hint
For possibility questions, your goal is to prove that one option can work. Once you've successfully built a valid scenario for an option, you've found the correct answer and can move on.
Updated On: Oct 1, 2025
- M occupies position 4 and P occupies position 5.
- P occupies position 4 and V occupies position 5.
- S occupies position 2 and P occupies position 3.
- P occupies position 2.
- S occupies position 5.
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
This is a "can be true" question, which asks us to find a possible scenario that is consistent with all the rules. The rules are: (1) P/T in 1; (2) S/T in 6; (3) M and O are a block; (4) V and T are a block. We test each option to see if a valid arrangement can be constructed.
Step 2: Detailed Explanation:
Let's test each option:
(A) M occupies position 4, P occupies position 5. `(_ _ _ M P _)` \begin{itemize} \item From Rule 3 ([MO] block), if M is in 4, O must be in 3. The arrangement becomes `(_ _ O M P _)`. \item From Rule 1 (P/T in 1), since P is in 5, T must be in 1. The arrangement becomes `(T _ O M P _)`. \item From Rule 4 ([VT] block), since T is in 1, V must be in 2. The arrangement becomes `(T V O M P _)`. \item The only magazine left is S, and the only position left is 6. The final arrangement is T, V, O, M, P, S. \item This arrangement is valid: T is in 1 (Rule 1 ok), S is in 6 (Rule 2 ok), OM are in 3-4 (Rule 3 ok), TV are in 1-2 (Rule 4 ok). \item Since a valid arrangement can be constructed, this option \textit{can be true}. \end{itemize} (B) P occupies 4, V occupies 5. `(_ _ _ P V _)` \begin{itemize} \item From Rule 4 ([VT] block), if V is in 5, T must be in 4 or 6. Position 4 is taken by P, so T must be in 6. `(_ _ _ P V T)`. \item From Rule 1 (P/T in 1), since T is in 6, P must be in 1. This contradicts the condition that P is in 4. Impossible. \end{itemize} (C) S occupies 2, P occupies 3. `(_ S P _ _ _)` \begin{itemize} \item From Rule 1 (P/T in 1), since P is in 3, T must be in 1. `(T S P _ _ _)`. \item From Rule 2 (S/T in 6), since T is in 1, S must be in 6. This contradicts the condition that S is in 2. Impossible. \end{itemize} (D) P occupies position 2. `(_ P _ _ _ _)` \begin{itemize} \item From Rule 1 (P/T in 1), since P is in 2, T must be in 1. `(T P _ _ _ _)`. \item From Rule 4 ([VT] block), since T is in 1, V must be in 2. This contradicts the condition that P is in 2. Impossible. \end{itemize} (E) S occupies position 5. `(_ _ _ _ S _)` \begin{itemize} \item From Rule 2 (S/T in 6), since S is not in 6, T must be in 6. `(_ _ _ _ S T)`. \item From Rule 4 ([VT] block), since T is in 6, V must be in 5. This contradicts the condition that S is in 5. Impossible. \end{itemize} Step 3: Final Answer:
Only the conditions in option (A) allow for the construction of a valid arrangement that does not violate any rules. Therefore, (A) is the correct answer.
This is a "can be true" question, which asks us to find a possible scenario that is consistent with all the rules. The rules are: (1) P/T in 1; (2) S/T in 6; (3) M and O are a block; (4) V and T are a block. We test each option to see if a valid arrangement can be constructed.
Step 2: Detailed Explanation:
Let's test each option:
(A) M occupies position 4, P occupies position 5. `(_ _ _ M P _)` \begin{itemize} \item From Rule 3 ([MO] block), if M is in 4, O must be in 3. The arrangement becomes `(_ _ O M P _)`. \item From Rule 1 (P/T in 1), since P is in 5, T must be in 1. The arrangement becomes `(T _ O M P _)`. \item From Rule 4 ([VT] block), since T is in 1, V must be in 2. The arrangement becomes `(T V O M P _)`. \item The only magazine left is S, and the only position left is 6. The final arrangement is T, V, O, M, P, S. \item This arrangement is valid: T is in 1 (Rule 1 ok), S is in 6 (Rule 2 ok), OM are in 3-4 (Rule 3 ok), TV are in 1-2 (Rule 4 ok). \item Since a valid arrangement can be constructed, this option \textit{can be true}. \end{itemize} (B) P occupies 4, V occupies 5. `(_ _ _ P V _)` \begin{itemize} \item From Rule 4 ([VT] block), if V is in 5, T must be in 4 or 6. Position 4 is taken by P, so T must be in 6. `(_ _ _ P V T)`. \item From Rule 1 (P/T in 1), since T is in 6, P must be in 1. This contradicts the condition that P is in 4. Impossible. \end{itemize} (C) S occupies 2, P occupies 3. `(_ S P _ _ _)` \begin{itemize} \item From Rule 1 (P/T in 1), since P is in 3, T must be in 1. `(T S P _ _ _)`. \item From Rule 2 (S/T in 6), since T is in 1, S must be in 6. This contradicts the condition that S is in 2. Impossible. \end{itemize} (D) P occupies position 2. `(_ P _ _ _ _)` \begin{itemize} \item From Rule 1 (P/T in 1), since P is in 2, T must be in 1. `(T P _ _ _ _)`. \item From Rule 4 ([VT] block), since T is in 1, V must be in 2. This contradicts the condition that P is in 2. Impossible. \end{itemize} (E) S occupies position 5. `(_ _ _ _ S _)` \begin{itemize} \item From Rule 2 (S/T in 6), since S is not in 6, T must be in 6. `(_ _ _ _ S T)`. \item From Rule 4 ([VT] block), since T is in 6, V must be in 5. This contradicts the condition that S is in 5. Impossible. \end{itemize} Step 3: Final Answer:
Only the conditions in option (A) allow for the construction of a valid arrangement that does not violate any rules. Therefore, (A) is the correct answer.
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Question: 5
If V occupies position 4, then T must occupy the position that is numbered exactly one lower than the position occupied by
If V occupies position 4, then T must occupy the position that is numbered exactly one lower than the position occupied by
Show Hint
Deconstruct complex question stems carefully. "T's position is one lower than X's position" is just another way of saying "X is in the position immediately after T."
Updated On: Oct 1, 2025
- M
- O
- P
- S
- V
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
This is a conditional deduction question. We are given a new piece of information (V is in 4) and must determine a specific relationship that results. The question's wording is complex: we need to find T's position, and then find which magazine is in the position numbered one higher than T.
Step 2: Detailed Explanation:
Let's build the arrangement with the new condition: V is in position 4. `(_ _ _ V _ _)` \begin{enumerate} \item Apply Rule 4 ([VT] block): Since V is in 4, T must be adjacent, either in position 3 or 5. \item Case 1: T is in 3. The arrangement is `(_ _ T V _ _)`. \begin{itemize} \item Apply Rule 1 (P/T in 1): T is not in 1, so P must be in 1. `(P _ T V _ _)`. \item Apply Rule 2 (S/T in 6): T is not in 6, so S must be in 6. `(P _ T V _ S)`. \item The remaining magazines, M and O, must fill positions 2 and 5. Rule 3 requires them to be in a consecutive block, but positions 2 and 5 are not consecutive. \item Therefore, Case 1 is impossible. \end{itemize} \item Case 2: T is in 5. The arrangement is `(_ _ _ V T _)`. \begin{itemize} \item Apply Rule 2 (S/T in 6): T is not in 6, so S must be in 6. `(_ _ _ V T S)`. \item Apply Rule 1 (P/T in 1): T is not in 1, so P must be in 1. `(P _ _ V T S)`. \item The remaining magazines, M and O, must fill the consecutive positions 2 and 3. This is allowed by Rule 3. \item The final arrangement must be: P, (M/O), (O/M), V, T, S. \end{itemize} \item This is the only possible outcome. So, if V is in 4, then T must be in 5 and S must be in 6. \end{enumerate} Step 3: Answering the Question:
The question asks: T's position (which is 5) must be "exactly one lower than the position occupied by" which magazine?
This means we are looking for the magazine in position \(5 + 1 = 6\).
From our deduction, the magazine in position 6 is S.
Step 4: Final Answer:
If V is in 4, T must be in 5, which is one position lower than position 6, occupied by S. Therefore, (D) is the correct answer.
This is a conditional deduction question. We are given a new piece of information (V is in 4) and must determine a specific relationship that results. The question's wording is complex: we need to find T's position, and then find which magazine is in the position numbered one higher than T.
Step 2: Detailed Explanation:
Let's build the arrangement with the new condition: V is in position 4. `(_ _ _ V _ _)` \begin{enumerate} \item Apply Rule 4 ([VT] block): Since V is in 4, T must be adjacent, either in position 3 or 5. \item Case 1: T is in 3. The arrangement is `(_ _ T V _ _)`. \begin{itemize} \item Apply Rule 1 (P/T in 1): T is not in 1, so P must be in 1. `(P _ T V _ _)`. \item Apply Rule 2 (S/T in 6): T is not in 6, so S must be in 6. `(P _ T V _ S)`. \item The remaining magazines, M and O, must fill positions 2 and 5. Rule 3 requires them to be in a consecutive block, but positions 2 and 5 are not consecutive. \item Therefore, Case 1 is impossible. \end{itemize} \item Case 2: T is in 5. The arrangement is `(_ _ _ V T _)`. \begin{itemize} \item Apply Rule 2 (S/T in 6): T is not in 6, so S must be in 6. `(_ _ _ V T S)`. \item Apply Rule 1 (P/T in 1): T is not in 1, so P must be in 1. `(P _ _ V T S)`. \item The remaining magazines, M and O, must fill the consecutive positions 2 and 3. This is allowed by Rule 3. \item The final arrangement must be: P, (M/O), (O/M), V, T, S. \end{itemize} \item This is the only possible outcome. So, if V is in 4, then T must be in 5 and S must be in 6. \end{enumerate} Step 3: Answering the Question:
The question asks: T's position (which is 5) must be "exactly one lower than the position occupied by" which magazine?
This means we are looking for the magazine in position \(5 + 1 = 6\).
From our deduction, the magazine in position 6 is S.
Step 4: Final Answer:
If V is in 4, T must be in 5, which is one position lower than position 6, occupied by S. Therefore, (D) is the correct answer.
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Question: 6
If S and V, not necessarily in that order, occupy consecutively numbered positions, which of the following must be true?
If S and V, not necessarily in that order, occupy consecutively numbered positions, which of the following must be true?
Show Hint
When a new rule links together existing "actors" (in this case, linking the V from the VT block to S), you often create a larger, more constrained block. The first thing to do is analyze the properties of this new super-block and see how it interacts with the most restrictive rules of the game.
Updated On: Oct 1, 2025
- M occupies position 4.
- O occupies position 2.
- P occupies position 1.
- S occupies position 6.
- T occupies position 6.
Show Solution
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
This is another conditional deduction question. The new condition connects two existing rules, which should lead to a strong, certain conclusion. We need to find what "must be true" under this new condition.
Step 2: Detailed Explanation:
\begin{enumerate} \item Analyze the Rules and Condition: \begin{itemize} \item Original Rule 4: V and T form a consecutive block ([VT] or [TV]). \item New Condition: S and V form a consecutive block ([SV] or [VS]). \end{itemize} \item Combine the rules: Since V must be next to both T and S, these three magazines must form a 3-magazine super-block: S-V-T or T-V-S. \item Test the position of T: The key to this game is the placement of T, which affects both end positions (1 and 6). \item Can T be in position 1? \begin{itemize} \item If T is in position 1, then from Rule 4, V must be in position 2. \item The combined block must be T-V-S, so S would have to be in position 3. The arrangement starts `T V S _ _ _`. \item However, Rule 2 states that if T is not in position 6, S must be. Since T is in 1, S must be in 6. \item This creates a contradiction: S cannot be in both position 3 and position 6. \item Therefore, T cannot be in position 1. \end{itemize} \item Deduce the occupant of position 1: \begin{itemize} \item According to Rule 1, position 1 must be either P or T. \item We have just proven that T cannot be in position 1. \item Therefore, P must be in position 1. \end{itemize} \end{enumerate} Step 3: Final Answer:
The new condition, when combined with the original rules, makes it impossible for T to be in position 1. Since position 1 must be either P or T, P is forced into position 1. This is a necessary conclusion. Therefore, (C) must be true.
For completeness, a possible arrangement is P, M, O, S, V, T. This satisfies P=1, T=6, [MO] in 2-3, [SV] in 4-5, and [VT] in 5-6.
This is another conditional deduction question. The new condition connects two existing rules, which should lead to a strong, certain conclusion. We need to find what "must be true" under this new condition.
Step 2: Detailed Explanation:
\begin{enumerate} \item Analyze the Rules and Condition: \begin{itemize} \item Original Rule 4: V and T form a consecutive block ([VT] or [TV]). \item New Condition: S and V form a consecutive block ([SV] or [VS]). \end{itemize} \item Combine the rules: Since V must be next to both T and S, these three magazines must form a 3-magazine super-block: S-V-T or T-V-S. \item Test the position of T: The key to this game is the placement of T, which affects both end positions (1 and 6). \item Can T be in position 1? \begin{itemize} \item If T is in position 1, then from Rule 4, V must be in position 2. \item The combined block must be T-V-S, so S would have to be in position 3. The arrangement starts `T V S _ _ _`. \item However, Rule 2 states that if T is not in position 6, S must be. Since T is in 1, S must be in 6. \item This creates a contradiction: S cannot be in both position 3 and position 6. \item Therefore, T cannot be in position 1. \end{itemize} \item Deduce the occupant of position 1: \begin{itemize} \item According to Rule 1, position 1 must be either P or T. \item We have just proven that T cannot be in position 1. \item Therefore, P must be in position 1. \end{itemize} \end{enumerate} Step 3: Final Answer:
The new condition, when combined with the original rules, makes it impossible for T to be in position 1. Since position 1 must be either P or T, P is forced into position 1. This is a necessary conclusion. Therefore, (C) must be true.
For completeness, a possible arrangement is P, M, O, S, V, T. This satisfies P=1, T=6, [MO] in 2-3, [SV] in 4-5, and [VT] in 5-6.
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