A molecule (P) on treatment with acid undergoes rearrangement and gives (Q). (Q) on ozonolysis followed by reflux under alkaline condition gives (R). The structure of (R) is given below. The structure of (P) is:




The first reaction on 'P' is treatment with acid which causes a rearrangement giving 'Q'. Then 'Q' undergoes ozonolysis followed by reflux with alkali to produce 'R'. Ozonolysis will cleave the double bond so let's label the side to add at ketone. Ozonolysis followed by reflux with alkali gives the ketone functionality is. The given product can undergo aldol condensation
If the product given here after reflux with alkali would produce
Given product means Q after ozonolysis with alkaline treatment gave. The first reaction involves acid that give is that the alcohol give alkylene as show n by structure.
Hence, Both Option 2 and 3 are Correct.

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,