A molecule (P) on treatment with acid undergoes rearrangement and gives (Q). (Q) on ozonolysis followed by reflux under alkaline condition gives (R). The structure of (R) is given below. The structure of (P) is:




The first reaction on 'P' is treatment with acid which causes a rearrangement giving 'Q'. Then 'Q' undergoes ozonolysis followed by reflux with alkali to produce 'R'. Ozonolysis will cleave the double bond so let's label the side to add at ketone. Ozonolysis followed by reflux with alkali gives the ketone functionality is. The given product can undergo aldol condensation
If the product given here after reflux with alkali would produce
Given product means Q after ozonolysis with alkaline treatment gave. The first reaction involves acid that give is that the alcohol give alkylene as show n by structure.
Hence, Both Option 2 and 3 are Correct.

Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 






In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 