A mixture of toluene (40%) and benzene (60%) is fed to the distillation column; recovery of benzene is 20% at the top. What is the ratio of the flow rate of benzene from Distillate to the bottoms? (Based on 1000 Kg of feed)?
A mixture of toluene (40%) and benzene (60%) is fed to the distillation column; recovery of benzene is 20% at the top. What is the ratio of the flow rate of benzene from Distillate to the bottoms? (Based on 1000 Kg of feed)?
Show Hint
- 0.6
- 0.2
- 0.25
- 0.4
The Correct Option is B
Solution and Explanation
- Given:
- Benzene in feed = 60% of 1000 kg = 600 kg
- Recovery of benzene at the top = 20% of 600 kg = 120 kg
- Benzene at the bottom = 600 kg - 120 kg = 480 kg
- The ratio of benzene from distillate to bottoms is \[ {Ratio} = \frac{120}{480} = 0.2 \]
Conclusion: The correct answer is option (B).
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