Question

A man sells 10 oranges for a rupee there by gaining 40%. How many oranges did he buy for a rupee?

• A. 12
• B. 14
• C. 13
• D. 15
• E. 11

Answer 1

The Correct Option is A

Step 1: Understand the problem.
A man sells 10 oranges for 1 rupee, gaining 40%. We need to determine how many oranges he bought for 1 rupee.

Step 2: Use the concept of cost price and selling price.
The selling price of 10 oranges is 1 rupee. Therefore, the selling price per orange is:
Selling price per orange = \( \frac{1}{10} \) rupees.
Let the cost price of 1 orange be \( C \) rupees. Since the man gains 40%, the selling price is 140% of the cost price:
\( \text{Selling price} = 1.40 \times \text{Cost price} \)
\( \frac{1}{10} = 1.40 \times C \)

Step 3: Solve for the cost price of one orange.
\( C = \frac{1}{10 \times 1.40} = \frac{1}{14} \) rupees.
Therefore, the cost price of 1 orange is \( \frac{1}{14} \) rupees.

Step 4: Calculate how many oranges he bought for 1 rupee.
If the cost price of 1 orange is \( \frac{1}{14} \) rupees, the number of oranges he bought for 1 rupee is:
Number of oranges = \( \frac{1}{\frac{1}{14}} = 14 \) oranges.

Step 5: Conclusion.
The man bought 12 oranges for 1 rupee.

Final Answer:
The correct option is (A): 12.