Question:
A line drawn through the point \(P(4,7)\) cuts the circle \(x^2+y^2=9\) at the points \(A\) and \(B\). Then \(PA\cdot PB\) is equal to :
A line drawn through the point \(P(4,7)\) cuts the circle \(x^2+y^2=9\) at the points \(A\) and \(B\). Then \(PA\cdot PB\) is equal to :
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Power of \(P(4,7)\) w.r.t. \(x^2+y^2-9=0\) is \(4^2+7^2-9=16+49-9=56\).
For any secant through \(P\), \(PA\cdot PB\) equals this power.
Answer: (2) 56
For any secant through \(P\), \(PA\cdot PB\) equals this power.
Answer: (2) 56
Updated On: Nov 11, 2026
- \(53\)
- \(56\)
- \(74\)
- \(65\)
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The Correct Option is B
Solution and Explanation
\(PA\cdot PB\) is the power of the point \(P\) with respect to the circle.
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