Question:
A light green coloured solution of sulphate salt of metal 'P' is taken in a beaker, a rod of another metal 'Q' is put in this solution as shown in the following figures:
A light green coloured solution of sulphate salt of metal 'P' is taken in a beaker, a rod of another metal 'Q' is put in this solution as shown in the following figures:
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When a more reactive metal displaces a less reactive metal from its solution, this is called a displacement reaction. The reactivity series can help predict which metal will displace another.
Updated On: Jan 13, 2026
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Solution and Explanation
Step 1: Identifying metals. - Metal 'P' (Cu) is displaced by metal 'Q' (Zn) in the solution. - Zinc (Zn) is more reactive than copper (Cu), as shown in the reactivity series, which allows zinc to displace copper from its sulphate solution.
Step 2: Writing the chemical equation. The reaction can be represented as: \[ {Zn (s)} + {CuSO}_4 (aq) \rightarrow {Cu (s)} + {ZnSO}_4 (aq) \]
Step 3: Conclusion from the reactivity series. - Zinc (Zn) is more reactive than Copper (Cu), and this is consistent with the reactivity series of metals. More reactive metals can displace less reactive metals from their compounds.
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