Question

(A) is hydrocarbon

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

In organic reactions, when dealing with aromatization and Friedel–Crafts reactions, remember that aromatic rings are typically formed from alkanes, and alkylation is used to add alkyl groups to the ring.

Answer 1

The Correct Option is A

Step 1: Analyze the reaction.
The first part of the reaction shows aromatization of the hydrocarbon using \( \text{Cr}_2\text{O}_3 \) at high temperatures (773K), which converts the alkane into a benzene ring. The presence of hydrogen and a nickel catalyst further reduces or saturates the carbon-carbon bonds in the compound.
Step 2: Understand the second part of the reaction.
The reaction with anhydrous \( \text{AlCl}_3 \) and hydrochloric acid (\( \text{HCl} \)) suggests a Friedel–Crafts alkylation, a reaction commonly used to attach alkyl groups to an aromatic ring.
Step 3: Conclusion.
The given reaction suggests that the hydrocarbon (A) is butane (\( \text{CH}_3 \text{CH}_2 \text{CH}_2 \text{CH}_3 \)), which upon aromatization and further alkylation, produces a benzene derivative. Therefore, the correct answer is option (A). Final Answer: (A) \(\text{CH}_3 \text{CH}_2 \text{CH}_2 \text{CH}_3\)