Question:
A horizontal disk has a radial frictionless slot in which a small block is confined to slide. The disk turns anticlockwise about its centre with a constant angular velocity of 3 rad/s.
If the block slides along the slot with a constant speed of 0.2 m/s relative to the slot, then the magnitude of Coriolis acceleration in \( \text{m/s}^2 \) is
A horizontal disk has a radial frictionless slot in which a small block is confined to slide. The disk turns anticlockwise about its centre with a constant angular velocity of 3 rad/s.
If the block slides along the slot with a constant speed of 0.2 m/s relative to the slot, then the magnitude of Coriolis acceleration in \( \text{m/s}^2 \) is
If the block slides along the slot with a constant speed of 0.2 m/s relative to the slot, then the magnitude of Coriolis acceleration in \( \text{m/s}^2 \) is
Show Hint
Use the Coriolis acceleration formula, twice the angular velocity times the relative sliding speed.
Updated On: Jul 27, 2026
- \( 1.2 \)
- \( 0.6 \)
- \( 2.4 \)
- \( 0.3 \)
Show Solution
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The Correct Option is A
Solution and Explanation
Step 1: Recall the Coriolis acceleration formula.
For a point sliding with relative speed \( v_r \) along a slot on a disk rotating at angular velocity \( \omega \), the Coriolis acceleration has magnitude \( a_c = 2\omega v_r \), directed perpendicular to the slot.
Step 2: Substitute the given values.
Here \( \omega = 3 \) rad/s and \( v_r = 0.2 \) m/s.
\[ a_c = 2 \times 3 \times 0.2 = 1.2 \ \text{m/s}^2 \]
Step 3: Check that no other term needs to be added.
Since the slot is radial and frictionless and the angular velocity is constant, there is no extra tangential acceleration term here; the question only asks for the Coriolis part.
Final Answer:
The magnitude of the Coriolis acceleration is 1.2 metres per second squared. \[ \boxed{a_c = 1.2 \ \text{m/s}^2} \]
For a point sliding with relative speed \( v_r \) along a slot on a disk rotating at angular velocity \( \omega \), the Coriolis acceleration has magnitude \( a_c = 2\omega v_r \), directed perpendicular to the slot.
Step 2: Substitute the given values.
Here \( \omega = 3 \) rad/s and \( v_r = 0.2 \) m/s.
\[ a_c = 2 \times 3 \times 0.2 = 1.2 \ \text{m/s}^2 \]
Step 3: Check that no other term needs to be added.
Since the slot is radial and frictionless and the angular velocity is constant, there is no extra tangential acceleration term here; the question only asks for the Coriolis part.
Final Answer:
The magnitude of the Coriolis acceleration is 1.2 metres per second squared. \[ \boxed{a_c = 1.2 \ \text{m/s}^2} \]
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