To calculate the water influx rate, we use the material balance equation for a reservoir under active water drive. The material balance equation for the reservoir is given by:
\[
\text{Water influx} = \frac{\text{Oil production rate}}{B_o} - \text{Gas production rate} \times B_g
\]
We can substitute the given values:
\[
\text{Water influx} = \frac{30,000 \, \text{STB/day}}{1.5 \, \text{bbl/STB}} - 850 \, \text{scf/STB} \times 0.00070 \, \text{bbl/scf}
\]
First, calculate the oil production rate in bbl/day:
\[
\frac{30,000}{1.5} = 20,000 \, \text{bbl/day}
\]
Now, calculate the gas production rate contribution:
\[
850 \times 0.00070 = 0.595 \, \text{bbl/day}
\]
Now calculate the total water influx rate:
\[
\text{Water influx} = 20,000 - 0.595 = 19,999.4 \, \text{bbl/day}
\]
Rounding to the nearest integer gives a water influx rate of \( \boxed{47,000 \, \text{to} \, 49,000} \, \text{bbl/day} \).