Given $\mu=$ refractive index of glass $=1.5 $
$t =$ thickness of coating,
$\mu=$ refractive index of coating $=1.8\, \lambda$
$=648 \times 10^{-9} m$
For constructive interference $2 \,\mu t=(2 n+1) \frac{\lambda}{2}$
$2 \times 1.8 \times t=\frac{648 \times 10^{-9}}{2}$
($t$ to be minimum $n =0$ )
$t=\frac{648}{2 \times 2 \times 1.8} \times 10^{-9} m$
$t=\frac{648}{7.2} \times 10^{-9} m=90 \,m$