Question

A friend is spotted by Lala at a distance of 200 m. When Lala starts to approach him, the friend also starts moving in the same direction as Lala. If the speed of his friend is 15 kmph, and that of Lala is 20 kmph, then how far will the friend have to walk before Lala meets him?

• A. 600 m
• B. 0.6 m
• C. 6 km
• D. 900 m
• E. 6 m

Hint:

When moving in the same direction, use relative speed (difference of speeds) to find the meeting time.

Answer 1

The Correct Option is A

Step 1: Converting Speeds:
Speeds in kmph: Lala = 20 kmph, Friend = 15 kmph.
Relative speed (since moving in same direction) = \(20 - 15 = 5\) kmph.
Initial distance = 200 m = 0.2 km.

Step 2: Time to Meet:
Time = \(\frac{\text{Distance}}{\text{Relative Speed}} = \frac{0.2}{5} = 0.04\) hours.

Step 3: Distance Walked by Friend:
Distance = Speed × Time = \(15 \times 0.04 = 0.6\) km = 600 m.