Question:
A fixed beam of span \(L\) rises by \(\Delta\) upwards at right hand support. The fixed end moment at right hand support will be
A fixed beam of span \(L\) rises by \(\Delta\) upwards at right hand support. The fixed end moment at right hand support will be
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Support settlement in a fixed beam:
\[
\boxed{
M=\frac{6EI\Delta}{L^2}
}
\]
The direction depends on whether the support rises or settles.
Updated On: Jul 23, 2026
- \(\dfrac{6EI\Delta}{L^2}\) clockwise
- \(\dfrac{6EI\Delta}{L^2}\) anticlockwise
- \(\dfrac{3EI\Delta}{L^2}\) clockwise
- \(\dfrac{3EI\Delta}{L^2}\) anticlockwise
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The Correct Option is A
Solution and Explanation
Step 1: Recall the fixed end moments due to sinking/rising of a support.
For a fixed beam when one support undergoes a settlement (or rise) of \(\Delta\),
\[
M=\frac{6EI\Delta}{L^2}.
\]
Step 2: Determine the direction. If the right support rises upward, the fixed end moment at the right support acts in the clockwise direction. Hence, \[ \boxed{ M_R=\frac{6EI\Delta}{L^2} \text{ (clockwise)} } \] Therefore, \[ \boxed{(A)} \] is the correct answer.
Step 2: Determine the direction. If the right support rises upward, the fixed end moment at the right support acts in the clockwise direction. Hence, \[ \boxed{ M_R=\frac{6EI\Delta}{L^2} \text{ (clockwise)} } \] Therefore, \[ \boxed{(A)} \] is the correct answer.
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