Question

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed how many times?

• A. 15
• B. 30
• C. 40
• D. 35
• E. 25

Hint:

This is a repeated problem from Section 1 (Q36). Identifying repeat questions can save time during the actual CET exam.

Answer 1

The Correct Option is B

Step 1: Analyse options.
- B kills 1/2 shots and misses 1/2 shots. - 27 misses for B means 27 kills and 54 total shots fired by B. - Ratio of shots A:B is 5:3. - Shots fired by A = $(5/3) \times 54 = 90$. - A kills 1 in 3 shots, so A's kills = $90 / 3 = 30$.
Step 2: Conclusion.
A has killed 30 times. Final Answer: (b) 30