Question:

A differentiable function \(f(x)\) is such that \(f(-0.1) = 2\), \(f(0) = 1\), and \(f(0.1) = 2\).

Then, \(\dfrac{d^2f}{dx^2}\) at \(x = 0\) is ______ (answer in integer).

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Use the standard three point central difference formula for the second derivative.
Updated On: Jul 28, 2026
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Correct Answer: 200

Solution and Explanation

Step 1: Pick the right numerical formula.
For a function known at three equally spaced points \(x_0 - h\), \(x_0\), \(x_0 + h\), the second derivative is estimated using the central difference formula: \[ f''(x_0) \approx \frac{f(x_0+h) - 2f(x_0) + f(x_0-h)}{h^2} \]
Here \(x_0 = 0\), \(h = 0.1\), \(f(-0.1) = 2\), \(f(0) = 1\), \(f(0.1) = 2\).

Step 2: Substitute the values.
\[ f''(0) \approx \frac{2 - 2(1) + 2}{(0.1)^2} = \frac{2}{0.01} \]

Step 3: Simplify.
\(\dfrac{2}{0.01} = 200\).

Final Answer:
The second derivative of \(f\) at \(x = 0\) works out to 200.
\[ \boxed{200} \]
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