Question

A die is thrown once. Probability of getting a number other than 3 is :

• A. \(\frac{1}{6}\)
• B. \(\frac{3}{6}\)
• C. \(\frac{5}{6}\)
• D. 1

Hint:

You can also use the complement rule: \(P(\text{not } E) = 1 - P(E)\). Here, \(1 - P(3) = 1 - 1/6 = 5/6\).

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
Probability is the number of favorable outcomes divided by the total number of possible outcomes. "Other than 3" means any number on the die except 3.
Step 2: Key Formula or Approach:
\[ P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]
Step 3: Detailed Explanation:
1. Possible outcomes when a die is thrown: {1, 2, 3, 4, 5, 6}. 2. Total number of outcomes = 6. 3. Favorable outcomes (numbers other than 3): {1, 2, 4, 5, 6}. 4. Number of favorable outcomes = 5. 5. Calculate probability: \[ P(\text{not 3}) = \frac{5}{6} \]
Step 4: Final Answer:
The probability is \(\frac{5}{6}\).