Using Boyle's law:
\( P_1 V_1 = P_2 V_2, \)
substitute \(P_1 = 50\) atm, \(V_1 = 50\) L, and \(P_2 = 1\) atm:
\( V_2 = \frac{P_1 V_1}{P_2} = \frac{50 \times 50}{1} = 2500 \text{ L}. \)
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

