Step 1: Understanding the deposition rate.
The shale sequence has a thickness of 10 m, and it was deposited over 10,000 years, implying a uniform rate of deposition. The rate of deposition is:
\[
\text{Deposition rate} = \frac{10 \, \text{m}}{10000 \, \text{years}} = 0.001 \, \text{m/year}
\]
Step 2: Calculating the number of samples.
To collect samples every 500 years, we need to calculate the number of 500-year intervals in the 10,000-year period:
\[
\text{Number of samples} = \frac{10000 \, \text{years}}{500 \, \text{years/sample}} = 20 \, \text{samples}
\]
Step 3: Conclusion.
The number of samples that must be collected is 20.
In a sedimentary succession shown in the figure, the last occurrence of the fossil species Q (dated 50 Ma) and the first occurrence of the fossil species R (dated 30 Ma) are recorded at Y and X, respectively. The estimated rate of sedimentation is (assume constant rate of sedimentation). 
Match the primary sedimentary structure in Group I with the corresponding process of formation in Group II.
\[\begin{array}{|l|l|} \hline \textbf{Group I} & \textbf{Group II} \\ \hline \text{P. Asymmetric ripples} & \text{1. Water escape} \\ \hline \text{Q. Dish and pillar} & \text{2. Bed load transportation of sediments} \\ \hline \text{R. Flute cast} & \text{3. Deposition from alternate traction and suspension load} \\ \hline \text{S. Wavy bedding} & \text{4. Scouring by turbulent eddy} \\ \hline \end{array}\]