A compound of vanadium chloride has spin only magnetic moment of 1.73 BM. Its formula is
Show Hint
- \(\mathrm{VCl_2}\)
- \(\mathrm{VCl_5}\)
- \(\mathrm{VCl_4}\)
- \(\mathrm{VCl_3}\)
The Correct Option is C
Solution and Explanation
V (Z = 23) = [Ar]3d3 4s2.
\(\mathrm{VCl_2}\): V2+ = d3 (n = 3). \(\mathrm{VCl_3}\): V3+ = d2 (n = 2). \(\mathrm{VCl_4}\): V4+ = d1 (n = 1). \(\mathrm{VCl_5}\): V5+ = d0 (n = 0, and does not exist).
Only \(\mathrm{VCl_4}\) has one unpaired electron.
Answer: (3) \(\mathrm{VCl_4}\)
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