Comprehension
A circle is drawn with the line joining the points (4, 3) and (8, 5) as diameter.
Question: 1

What are the coordinates of the centre of the circle ?

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Remember that the center is always the midpoint of any diameter. The midpoint formula is simply the average of the x-coordinates and the average of the y-coordinates.
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Solution and Explanation

We are given the coordinates of the two endpoints of a circle's diameter. We need to find the coordinates of the center of the circle.

The center of a circle is the midpoint of its diameter. The midpoint formula for two points (x₁, y₁) and (x₂, y₂) is:
Midpoint = ( (x₁ + x₂)/(2), (y₁ + y₂)/(2) ) The endpoints of the diameter are (x₁, y₁) = (4, 3) and (x₂, y₂) = (8, 5).
Let the coordinates of the center be (x, y). Using the midpoint formula:
x = (x₁ + x₂)/(2) = (4 + 8)/(2) = (12)/(2) = 6 y = (y₁ + y₂)/(2) = (3 + 5)/(2) = (8)/(2) = 4 So, the coordinates of the center of the circle are (6, 4).

The coordinates of the centre of the circle are (6, 4).
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Question: 2

If (5, 2) is a point on one end of another diameter, what are the coordinates of the other end of that diameter ?

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To find the other endpoint of a diameter when you have one endpoint and the center, simply think: "How did I get from the endpoint to the center, and then do the same step again?". To get from x=5 to x=6, we add 1. Add 1 again to 6 to get 7. To get from y=2 to y=4, we add 2. Add 2 again to 4 to get 6. The other end is (7, 6). This mental math is very fast.
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Solution and Explanation

We are considering the same circle from the previous question, so we know its center. We are given one endpoint of a new diameter and we need to find the other endpoint.

The center of the circle is the midpoint of the diameter. Let the known endpoint be (x₁, y₁) and the unknown endpoint be (x₂, y₂). Let the center be (xc, yc). The midpoint formula is:
xc = (x₁ + x₂)/(2) and yc = (y₁ + y₂)/(2) We can rearrange this to solve for the unknown endpoint coordinates:
x₂ = 2xc - x₁ and y₂ = 2yc - y₁ From part (i), the center of the circle is (xc, yc) = (6, 4).
The given endpoint of the new diameter is (x₁, y₁) = (5, 2).
Let the other endpoint be (x₂, y₂).
Using the rearranged midpoint formula:
x₂ = 2(6) - 5 = 12 - 5 = 7 y₂ = 2(4) - 2 = 8 - 2 = 6 So, the coordinates of the other end of the diameter are (7, 6).

The coordinates of the other end of that diameter are (7, 6).
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