A circle C1 passes through the origin O and has diameter 4 on the positive x-axis. The line y = 2x gives a chord OA of circle C1. Let C2 be the circle with OA as a diameter. If the tangent to C2 at the point A meets the x-axis at P and y-axis at Q, then QA :AP is equal to
The correct answer is (A) : 1 : 4
Equation of C1
x2 + y2 – 4x = 0
Intersection with
y = 2x
\(x^2+4x^2-4x = 0\)
\(5x^2-4x = 0\)
\(⇒ x = 0, \frac{4}{5}\)
\(y = 0, \frac{8}{5}\)
\(A : (\frac{4}{5}, \frac{8}{5})\)

Tangent of \(C_2\) at \(A(\frac{4}{5},\frac{8}{5})\)
x+2y = 4
\(⇒ P : (4,0), Q : (0,2)\)
\(QA : AP = 1:4\)
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