Step 1: Understanding the relationship.
In a Zener diode, the breakdown voltage is inversely proportional to the width of the depletion region. The breakdown voltage \( V \) can be related to the width of the depletion region \( W \) by the equation:
\[
V_1 W_1 = V_2 W_2
\]
Where:
- \( V_1 = 100V \) and \( W_1 = 20 \, \text{mm} \)
- \( W_2 = 1 \, \text{mm} \) (new width)
Step 2: Apply the relation.
Substitute the known values into the equation to solve for \( V_2 \):
\[
100 \times 20 = V_2 \times 1
\]
\[
V_2 = 100 \times 20 = 5V
\]
Step 3: Conclusion.
The Zener diode will have a breakdown voltage of 5V when the depletion region width is reduced to 1 mm. Therefore, the correct answer is (2) 5V.