Question

A cell of emf 2V is connected with a load of resistance 1.5Ω. The power delivered by the cell to the load is maximum, then power transferred to the load is

• A. 0.33 W
• B. 2.67 W
• C. 1.33 W
• D. 3.25 W

Hint:

For maximum power transfer, the load resistance should be equal to the internal resistance of the source. The power delivered to the load is then given by \( P = \frac{V^2}{4R} \).

Answer 1

The Correct Option is A

The power transferred to the load is given by the formula: \[ P = \frac{V^2}{4R} \] where: - \( V = 2 \text{ V} \) is the emf of the cell, - \( R = 1.5 \text{ Ω} \) is the resistance of the load. Substituting the values: \[ P = \frac{(2)^2}{4 \times 1.5} = \frac{4}{6} = 0.33 \text{ W} \] Thus, the correct answer is (A).