Instead of directly computing \( \frac{4}{52} \), we can think of the deck as split into 13 equally-sized rank groups, Aces, 2s, 3s, and so on up to Kings, each containing exactly 4 cards, one per suit. Drawing a random card is then equivalent to randomly picking one of these 13 groups.
Since the deck splits perfectly into 13 equally likely rank groups and Kings form exactly one such group, the probability works out to one in thirteen.
Therefore, the correct answer is 1/13.