Question:

A card is drawn at random from a well shuffled deck of 52 playing cards. The probability that it is either a ten or a king is

Show Hint

For mutually exclusive events, simply add the number of favorable outcomes of each event directly.
Always reduce the final fraction to its simplest form to match the given options.
Updated On: Jul 22, 2026
  • $\frac{1}{26}$
  • $\frac{2}{13}$
  • $\frac{1}{13}$
  • $\frac{8}{26}$
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
The question is based on the classical definition of probability using a standard deck of 52 playing cards.
We need to find the probability of drawing a card that is either a "ten" or a "king".

Step 2: Key Formula or Approach:
The probability of an event $E$ is given by:
\[ P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]
Since drawing a "ten" and drawing a "king" are mutually exclusive events (a single card cannot be both a ten and a king simultaneously), the total number of favorable outcomes is the sum of the individual favorable outcomes.

Step 3: Detailed Explanation:

• Find the total number of possible outcomes in a standard deck of playing cards:
\[ \text{Total cards in the deck, } n(S) = 52 \]

• Determine the number of "ten" cards in the deck:
There are 4 suits in a deck (Hearts, Diamonds, Clubs, Spades), and each suit contains exactly one 10.
\[ \text{Number of tens, } n(T) = 4 \]

• Determine the number of "king" cards in the deck:
Each of the 4 suits contains exactly one King.
\[ \text{Number of kings, } n(K) = 4 \]

• Since these are mutually exclusive events, calculate the total number of favorable outcomes:
\[ \text{Favorable outcomes, } n(T \cup K) = n(T) + n(K) = 4 + 4 = 8 \]

• Compute the probability of drawing either a ten or a king:
\[ P(T \cup K) = \frac{n(T \cup K)}{n(S)} = \frac{8}{52} \]

• Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 4:
\[ P(T \cup K) = \frac{2}{13} \]


Step 4: Final Answer:
The probability that the drawn card is either a ten or a king is $\frac{2}{13}$.
Was this answer helpful?
0
0

Top CBSE X Questions

View More Questions