Question

A carbonyl compound \( X(C_3H_6O) \) on oxidation gave carboxylic acid \( Y(C_3H_6O_2) \). The oxime of \( X \) is:

• A. \( \text{CH}_3\text{CH}_2\text{CH} = \text{NNH}_2 \)
• B. \( \text{CH}_3\text{CH}_2\text{CH} = \text{NOH} \)
• C. \( (\text{CH}_3)_2\text{C} = \text{N-NH}_2 \)
• D. \( (\text{CH}_3)_2\text{C} = \text{N-OH} \)
  \

Hint:

- Aldehydes and ketones react with hydroxylamine to form oximes. - Oxidation of aldehydes leads to the formation of carboxylic acids, while oxidation of ketones does not change the carbon count. - Recognizing molecular formulas and oxidation patterns helps in identifying functional groups.

Answer 1

The Correct Option is B

Step 1: Identifying the carbonyl compound - The molecular formula of \( X \) is \( C_3H_6O \), which corresponds to an aldehyde or ketone. - On oxidation, it gives \( Y(C_3H_6O_2) \), which is a carboxylic acid. - The possible structure of \( X \) is propanal \( (\text{CH}_3\text{CH}_2\text{CHO}) \). Step 2: Oxime Formation - Oximes are formed by the reaction of a carbonyl group with hydroxylamine (NH_2OH). - The oxime of propanal is propanal oxime \( (\text{CH}_3\text{CH}_2\text{CH} = \text{NOH}) \). Thus, the correct option is (2).