Question

A car dealer lost 6% on a car. Had he sold it for Rs 3600 more, he would have gained 6%. At what price did he buy the car?

• A. Rs.40,000
• B. Rs.24,000
• C. Rs. 30,000
• D. Rs. 36,000
• E. Rs.32,000

Answer 1

The Correct Option is C

Step 1: Understand the given information.
- The car dealer lost 6% on a car.
- Had he sold it for Rs. 3600 more, he would have gained 6%.
We need to find the price at which the car dealer bought the car.

Step 2: Let the cost price of the car be \( x \).
Let the cost price of the car be \( x \) rupees.
The selling price when the dealer incurs a loss of 6% is:
Selling price with loss = \( x - 0.06x = 0.94x \)
If the dealer had sold the car for Rs. 3600 more, the selling price would have been \( 0.94x + 3600 \), and he would have gained 6%.
The selling price with a 6% gain is:
Selling price with gain = \( x + 0.06x = 1.06x \)

Step 3: Set up the equation.
According to the problem, if the car were sold for Rs. 3600 more, the selling price would have been equal to the selling price with a 6% gain. Therefore, we can set up the equation:
\( 0.94x + 3600 = 1.06x \)

Step 4: Solve for \( x \).
Simplifying the equation:
\( 3600 = 1.06x - 0.94x \)
\( 3600 = 0.12x \)
\( x = \frac{3600}{0.12} = 30,000 \)

Step 5: Conclusion.
The cost price of the car is Rs. 30,000.

Final Answer:
The correct option is (C): Rs 30,000.