Question:
A cable of span \(10\,\mathrm{m}\) carries a uniformly distributed load of \(6\,\mathrm{kN/m}\) over the entire span. If the central dip is \(3\,\mathrm{m}\), the horizontal tension is
A cable of span \(10\,\mathrm{m}\) carries a uniformly distributed load of \(6\,\mathrm{kN/m}\) over the entire span. If the central dip is \(3\,\mathrm{m}\), the horizontal tension is
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For a cable subjected to uniformly distributed load,
\[
\boxed{H=\frac{wL^2}{8d}.}
\]
Updated On: Jul 23, 2026
- \(20\,\mathrm{kN}\)
- \(25\,\mathrm{kN}\)
- \(30\,\mathrm{kN}\)
- \(35\,\mathrm{kN}\)
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The Correct Option is B
Solution and Explanation
Step 1: Use the horizontal tension formula for a cable carrying UDL.
\[
H=\frac{wL^2}{8d},
\]
where
\[
w=6\,\mathrm{kN/m},\qquad
L=10\,\mathrm{m},\qquad
d=3\,\mathrm{m}.
\]
Step 2: Calculate the horizontal tension. \[ H=\frac{6\times10^2}{8\times3} =\frac{600}{24} =25\,\mathrm{kN}. \] Hence, \[ \boxed{25\,\mathrm{kN}} \] is the correct answer.
Step 2: Calculate the horizontal tension. \[ H=\frac{6\times10^2}{8\times3} =\frac{600}{24} =25\,\mathrm{kN}. \] Hence, \[ \boxed{25\,\mathrm{kN}} \] is the correct answer.
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