A borehole log of \(1.2\ \text{m}\) in length has recovered rock cores of lengths \(20,\ 8,\ 15,\ 8,\ 8,\ 4,\ 3,\ 9,\ 10,\ 1,\ 5,\) and \(10\ \text{cm}\). The RQD (in percentage) is
Show Hint
Only core pieces of length
\[
\boxed{\ge 10\ \text{cm}}
\]
are considered while calculating RQD.
Step 1: Recall the definition of Rock Quality Designation (RQD).
RQD is calculated as
\[
\boxed{
\text{RQD}
=
\frac{\text{Total length of core pieces } \ge 10\text{ cm}}
{\text{Total core run}}
\times100.
}
\]
Step 2: Find the total length of qualifying core pieces.
Core pieces having length at least \(10\) cm are
\[
20,\ 15,\ 10,\ 10\ \text{cm}.
\]
Hence,
\[
\text{Total qualifying length}
=
20+15+10+10
=
55\ \text{cm}.
\]
The borehole length is
\[
1.2\ \text{m}
=
120\ \text{cm}.
\]
Therefore,
\[
\text{RQD}
=
\frac{55}{120}\times100
=
45.83\%.
\]
Thus,
\[
\boxed{45.8\%}
\]
is the correct answer.
Therefore,
\[
\boxed{(C)}
\]
is the correct answer.