(ii) t
Mass of the body = m
Acceleration of the body = a
Using Newton’s second law of motion, the force experienced by the body is given by the equation:
F = ma
Both m and a are constants. Hence, force F will also be constant.
F= ma = Constant … (i)
For velocity v, acceleration is given as, a = dv / dt = constant
dv = Constant × dt
v = at ....(ii)
Where, a is another constant
v ∝ t ...(iii)
Power is given by the relation: P = F.v
Using equations (i) and (iii), we have: p ∝ t
Hence, power is directly proportional to time.
A rain drop of radius 2 mm falls from a height of 500 m above the ground. It falls with decreasing acceleration (due to viscous resistance of the air) until at half its original height, it attains its maximum (terminal) speed, and moves with uniform speed thereafter. What is the work done by the gravitational force on the drop in the first and second half of its journey ? What is the work done by the resistive force in the entire journey if its speed on reaching the ground is 10 m s–1 ?
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
W = Force × Distance
Where,
Work (W) is equal to the force (f) time the distance.
W = F d Cos θ
Where,
W = Amount of work, F = Vector of force, D = Magnitude of displacement, and θ = Angle between the vector of force and vector of displacement.
The SI unit for the work is the joule (J), and it is defined as the work done by a force of 1 Newton in moving an object for a distance of one unit meter in the direction of the force.
Work formula is used to measure the amount of work done, force, or displacement in any maths or real-life problem. It is written as in Newton meter or Nm.