Question

A bag contains 3 red balls, 5 white balls, and 7 black balls. What is the probability that a ball drawn from the bag at random will be neither red nor black?

• A. \(\frac{1}{5}\)
• B. \(\frac{1}{3}\)
• C. \(\frac{7}{15}\)
• D. \(\frac{8}{15}\)

Hint:

To find the probability of drawing a specific type of object, divide the number of favorable outcomes by the total number of possible outcomes.

Answer 1

The Correct Option is B

Step 1: Total number of balls in the bag = \( 3 + 5 + 7 = 15 \). Step 2: The number of balls that are neither red nor black are the white balls, which are 5 in number. \[ \text{Number of favorable outcomes} = 5 \text{ (white balls)} \] Step 3: The probability of drawing a ball that is neither red nor black is: \[ P(\text{Neither red nor black}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of balls}} = \frac{5}{15} = \frac{1}{3} \] Thus, the probability is \(\frac{1}{3}\).