Step 1: Understanding membrane fluidity.
At higher temperatures, bacterial membranes tend to become more fluid, which can lead to instability. To counteract this, bacteria incorporate saturated fatty acids into their membranes to decrease fluidity and maintain structural integrity.
Step 2: Analyzing the options.
(A) long chain fatty acids: Long-chain fatty acids tend to increase membrane rigidity, but they are not as effective at maintaining membrane stability at high temperatures compared to saturated fatty acids.
(B) short chain fatty acids: Short-chain fatty acids tend to increase membrane fluidity, which would be less beneficial for bacterial survival at higher temperatures.
(C) unsaturated fatty acids: Unsaturated fatty acids increase membrane fluidity, which would not be beneficial at higher temperatures as it would make the membrane too fluid.
(D) saturated fatty acids: Correct — Saturated fatty acids are beneficial for maintaining membrane integrity at high temperatures because they reduce membrane fluidity and increase membrane stability.
Step 3: Conclusion.
The correct answer is (D) saturated fatty acids, as they help maintain membrane stability at high temperatures.
Which one of the following matches is CORRECT between the inhibitors given in Group A with their modes of action in Group B?
\[\begin{array}{|c|c|} \hline Group A & Group B \\ \hline \text{(P) Antimycin A} & \text{(i) Inhibits cytochrome c oxidase} \\ \hline \text{(Q) Amytal} & \text{(ii) Blocks electron transfer from cyt b to cyt c1} \\ \hline \text{(R) Carbon monoxide} & \text{(iii) Inhibits adenine nucleotide translocase} \\ \hline \text{(S) Atractyloside} & \text{(iv) Prevents electron transfer from Fe-S centers of complex 1 to ubiquinone} \\ \hline \end{array}\]