Question

A 45-year-old man is evaluated for electrolyte imbalance: \(Na^+ = 130\) mmol/L, \(Cl^- = 84\) mmol/L, \(HCO_3^- = 16\) mmol/L. What is his anion gap?

• A. 26
• B. 30
• C. 18
• D. 22

Hint:

Anion gap formula: \[ AG = Na^+ - (Cl^- + HCO_3^-) \]

Answer 1

The Correct Option is B

Concept: Anion gap is calculated using: \[ \text{Anion gap} = Na^+ - (Cl^- + HCO_3^-) \]

Step 1: Substitute values.
\[ Na^+ = 130,\quad Cl^- = 84,\quad HCO_3^- = 16 \]

Step 2: Apply formula.
\[ \text{Anion gap}=130-(84+16) \]

Step 3: Calculate.
\[ \text{Anion gap}=130-100=30 \]