Question

A 24 cm line AB is vertically standing on a horizontal plane. The station point is located 18 cm above ground and 15 cm in front of the line AB. The picture plane is located in between the line AB and station point perpendicular to the sight line. The distance between the picture plane and the station point is 9 cm. The height of the perspective view of the line AB is ________cm. (rounded off to one decimal place)

Hint:

When performing perspective drawing calculations, be sure to use formula involving the correct scaling factors. The method employed can be adjusted, with more

Answer 1

Given:
Length of line AB = 24 cm
Height of the station point above the ground = 18 cm
Distance between the station point and the line AB = 15 cm
Distance between the picture plane and the station point = 9 cm
Step 1: Use the formula for perspective view height: \[ {Height of perspective view} = \frac{h_1 \times d_2}{d_1 + d_2} \] Where:
\( h_1 = 18 \, {cm} \) (height of the station point)
\( d_1 = 15 \, {cm} \) (distance from the station point to line AB)
\( d_2 = 9 \, {cm} \) (distance between the station point and the picture plane)
Step 2: Substitute the given values: \[ {Height of perspective view} = \frac{18 \times 9}{15 + 9} = \frac{162}{24} = 6.75 \, {cm} \] The height value is \( 6.75 \, {cm} \)