Step 1: Understanding the Question:
We are given the power rating (\(100\text{ W}\)) and the operating voltage (\(220\text{ V}\)) of an electric lamp. We need to calculate the electric current flowing through it during normal operation.
Step 2: Key Formula or Approach:
The relationship between electric power (\(P\)), voltage (\(V\)), and current (\(I\)) is:
\[ P = V \cdot I \implies I = \frac{P}{V} \]
Step 3: Detailed Explanation:
• Given values:
Power (\(P\)) = \(100\text{ W}\)
Voltage (\(V\)) = \(220\text{ V}\)
• Substitute these values into the current formula:
\[ I = \frac{100}{220} \]
• Simplify the fraction by dividing the numerator and the denominator by their greatest common divisor, which is 20:
\[ I = \frac{100 \div 20}{220 \div 20} = \frac{5}{11}\text{ A} \]
• Expressed in decimals, this is approximately \(0.454\text{ A}\). However, the options are given in fractional form, matching \(\frac{5}{11}\text{ amp}\).
Step 4: Final Answer:
The current taken by the lamp is \(\frac{5}{11}\text{ amp}\).