Step 1: Understanding the Concept:
This question uses one of the fundamental Pythagorean identities in trigonometry.
Step 2: Key Formula or Approach:
The relevant trigonometric identity is:
\[
\sec^2 A - \tan^2 A = 1
\]
Step 3: Detailed Explanation:
The given expression is \(7 \sec^2 A - 7 \tan^2 A\).
We can see that 7 is a common factor in both terms. Let's factor it out:
\[
7 (\sec^2 A - \tan^2 A)
\]
Now, we substitute the value of the identity \(\sec^2 A - \tan^2 A = 1\) into the expression:
\[
= 7 (1)
\]
\[
= 7
\]
Step 4: Final Answer:
The value of the expression is 7. This corresponds to option (B).
Find the mean of the following distribution:
\[\begin{array}{|c|c|c|c|c|c|c|c|} \hline \textbf{Class-interval} & 11-13 & 13-15 & 15-17 & 17-19 & 19-21 & 21-23 & 23-25 \\ \hline \text{Frequency} & \text{7} & \text{6} & \text{9} & \text{13} & \text{20} & \text{5} & \text{4} \\ \hline \end{array}\]