Question

5.33 g of \(CrCl_3 \cdot 6H_2O\), which is a 1:3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with \(AgNO_3\), results in 8.61 g of \(AgCl\). The ratio of moles of complex reacted and moles of \(AgCl\) formed is ______ \(\times 10^{-2}\). (Nearest integer)} \[ [Molar\ mass: Cr = 52,\ Ag = 108,\ Cl = 35.5,\ H = 1,\ O = 16] \]

Answer 1

Correct Answer: 25

Step 1:Find molar mass of \(CrCl_3 \cdot 6H_2O\)} \[ = 52 + 3(35.5) + 6(18) \] \[ = 52 + 106.5 + 108 \] \[ = 266.5 \]
Step 2:Moles of complex} \[ \frac{5.33}{266.5} = 0.02\ \text{mol} \]
Step 3:Moles of \(AgCl\)} \[ Molar\ mass\ of\ AgCl = 108 + 35.5 = 143.5 \] \[ \frac{8.61}{143.5} = 0.06\ \text{mol} \]
Step 4:Required ratio} \[ \frac{0.02}{0.06} = \frac{1}{3} = 0.333 \] \[ 0.333 \times 10^{-2} \] Nearest integer: \[ \boxed{25} \]