Question

30 gm of sugar was mixed in 180 ml of water in a vessel A, 40 gm of sugar was mixed in 280 ml of water in vessel B, and 20 gm of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is:

• A. Sweeter than C.
• B. Sweeter than that in A.
• C. As sweet as that in C.
• D. Less sweet than that in C.

Hint:

To compare the sweetness, calculate the concentration of sugar in each solution.

Answer 1

The Correct Option is D

Sugar concentration is used to determine the sweetness of a solution. We calculate the sugar concentration by dividing the sugar quantity by the total solution volume, then convert to a percentage. Let's compute:
Vessel A:
Sugar weight = 30 gm
Total volume = 180 ml + 30 gm ≈ 210 ml (assuming density of sugar similar to water for simplicity)
Concentration = (30/210) × 100 ≈ 14.29%
Vessel B:
Sugar weight = 40 gm
Total volume = 280 ml + 40 gm ≈ 320 ml
Concentration = (40/320) × 100 = 12.50%
Vessel C:
Sugar weight = 20 gm
Total volume = 100 ml + 20 gm ≈ 120 ml
Concentration = (20/120) × 100 = 16.67%
Comparing concentrations:

• A: 14.29%
• B: 12.50%
• C: 16.67%

Thus, the solution in vessel B is less sweet than that in C.