Given:
\( 25^{190} - 8^{190} \) is divisible by \( 25 - 8 = 17 \)
\( 19^{190} - 2^{190} \) is divisible by \( 19 - 2 = 17 \)
\( 25^{190} - 19^{190} \) is divisible by \( 25 - 19 = 6 \)
\( 8^{190} - 2^{190} \) is divisible by \( 8 - 2 = 6 \)
Now, we calculate the least common multiple (L.C.M.) of 1746:
The L.C.M. of 1746 is 34.
Therefore, the number is divisible by 34 but not by 14.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)